Echo in for loop

Answer 1

After your edit, it looks like this is your main problem:

$date = 2015-02-30;

This is not what you think it is. It should be quoted like this:

$date = '2015-02-30';

Otherwise, $date is a not a string, it's a math expression that evaluates to (int) 1983, so substr($date, 8, 2); will evaluate to false, not 30, and then obviously your option won't be selected.