It would seem that having a sequence point is immaterial in the expression b=++a + ++a;
That is, whether the first ++a is evaluated first or the second ++a is evaluated first in either case a is incremented twice and then the + operator takes effect, so the eventual equation is either b = 2 + 3; or b = 3 + 2 thus b = 5.
When I get home I will try this on with my C compiler.
Blastfurnace's comment about both being evaluated before the + operator takes effect is correct, and now that I think about it, obvious.
That is, + is lower in precedence than ++a. It could be argued that this statement is NOT ambiguous in that switching the order of evaluation (R to L or L to R, both with respect to precedence) results in the same answer.
No one will claim this is well written code, interesting on several points for a discussion, but not something that should be endorsed.
