how to grep one string occuring multiple times from same file

Question

I want to capture a string 1 row affected... But problem is there are no of such string present in the same file.

My concern to capture 1 row affecte

Answer 1

Assuming some input like

$ printf "1 row affected...\nsomeline\nsomeline\nJob completed successfully\nsomeline\nsomeline\n2 row affected...\n3 row affected...\n"
1 row affected...
someline
someline
Job completed successfully
someline
someline
2 row affected...
3 row affected...

Let's say you only want the first row after "Job completed successfully" that contains "row affected". You can pipe it like so

| sed -n -e '/Job completed successfully/,$p' | grep -m 1 "affected"

e.g

$ printf "1 row affected...\nsomeline\nsomeline\nJob completed successfully\nsomeline\nsomeline\n2 row affected...\n3 row affected...\n" | sed -n -e '/Job completed successfully/,$p' | grep -m 1 "row affected"
2 row affected...

Where the sed matches any line containing Job completed successfully and returns from that line to the end of the file and grep -m NUM shows only the first NUM matches of grep. Could probably do it with one sed thought that gets more messy. If grep -m NUM is unavailable, you can just pipe to head, e.g.

| sed -n -e '/Job completed successfully/,$p' | grep "affected" | head -n 1