Getting time limit exceeded on submitting answer. I am also facing same problem with 2-3 more questions that I have submitted on spoj.com.
http://www.spoj.com/problems/
Your algorithm is O((m-n)*n) which of course won't run within the allocated time limit. Let's go over your code:
count=0;
for(k=1;k<=j/2;k++)
{
if(j%k==0)
count++;
if(count>1)
break;
}
if(count==1)
printf("%lld\n",j);
Micro optimization: Why do you need a counter? You could get away with a bool.
Optimization: Why are you testing primes j/2
? If j
has a divisor greater than 1 than it's guaranteed that j
has a divisor that's at most sqrt(j)
.
Micro Optimization: Don't consider even numbers at all, except for 2.
bool prime = j==2 || j%2==1 ;
for(k=2;prime && k*k<=j;k++)
{
if(j%k==0) prime = false;
}
}
if(prime) printf("%lld\n",j);
Now this is O((m-n)*sqrt(n)) which is a lot faster.
I suppose this won't make the limit. You could extend the second micro-optimization to skip numbers divisible by 3 very easy.
Optimization: If this is still not enough then you have to do a pseudo-primality test. One test that's very easy to implement in O(log(n)) is https://en.wikipedia.org/wiki/Fermat_primality_test. With this the complexity is down to O((m-n)*log(n)) which should be run in the available time limit.