Count the number of executable files in bash

Question

I have seen a lot of answers about this subject but I don\'t want to do this using find. I have written this but something not working:

function Cou         


        

Answer 1

To count the number of executable (like the title says)

 count=0 
 for file in yourdir/*; do 
     if [ -x $file ]; then 
         count=$((count+1)); 
     fi; 
 done; 
 echo "total ${count}"

To count folders, just change the -x test with -d