Group an array to form three arrays based on the index

Question

I want to sort an array in a way that it gives back three arrays. So

var myArray = [\'1\',\'2\',\'3\',\'1\',\'2\',\'3\',\'1\',\'2\',\'3\',\'1\',\'2\',\'3\',\'1\'         


        

Answer 1

If you're looking for high-order solution (using methods, like Array.prototype.reduce()) following approach might work:

const arr = ['1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3'];

const [arr1,arr2,arr3] = arr.reduce((res,e,i) => (res[i%3].push(e),res), [[],[],[]]);

console.log(`arr1 = ${JSON.stringify(arr1)}`);
console.log(`arr2 = ${JSON.stringify(arr2)}`);
console.log(`arr3 = ${JSON.stringify(arr3)}`);

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p.s. got a sneak peek at this (universal) solution to make mine a bit more compact