why printf behaves differently when we try to print character as a float and as a hexadecimal?

Question

I tried to print character as a float in printf and got output 0. What is the reason for this.
Also:

char c=\'z\';
printf(\"%f %X\",c,c);

Answer 1

You need to use a cast operator like this:

char c = 'z';

printf("%f %X", (float)c, c);

or

printf("%f %X", (double)c, c);

In Xcode, if I do not do this, I get the warning:

Format specifies specifies 'double' but the argument has type 'char', and the output is 0.000000.