I\'ve been searching the net for a couple of mornings and found nothing, hope you can help.
I have an anonymous function like this
f = @(x,y) [sin(2*pi*x
Defining an anonymous function f
as
f = @(x,y) [0,1];
naturally returns [0,1]
for any inputs x
and y
regardless of the length of those vectors.
This behavior puzzled me also until I realized that I expected f(a,b)
to loop over a
and b
as if I had written
for inc = 1:length(a)
f(a(inc), b(inc))
end
However, f(a,b)
does not loop over the length of its inputs, so it merely returns [0,1]
regardless of the length of a
and b
.
The desired behavior can be obtained by defining f
as
g=@(x,y)[zeros(size(x)),ones(size(y))]
as Daniel stated in his answer.