I have a dict and behind each key is a list stored. Looks like this:
dict with values: {
u\'New_York\': [(u\'New_York\', u\'NY\', datetime.datetime(2014, 8, 13,
Can you have a look at : https://wiki.python.org/moin/HowTo/Sorting#Sorting_Mini-HOW_TO
The answer may be :
In [2]: import datetime
In [3]: d = {
u'New_York': [(u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 10), (u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 4), (u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 3)],
u'Jersy': [(u'Jersy', u'JY', datetime.datetime(2014, 8, 13, 0, 0), 6), (u'Jersy', u'JY', datetime.datetime(2014, 8, 13, 0, 0), 7)],
u'Alameda': [(u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 1), (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 2), (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 3), (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 1)]
}
In [4]: def give_max_values(d):
...: res = {}
...: for key, vals in d.iteritems():
...: res[key] = max(vals, key=lambda x: x[3])
...: return res
In [5]: somedic = give_max_values(d)
In [6]: print somedic
{u'New_York': (u'New_York', u'NY', datetime.datetime(2014, 8, 13, 0, 0), 10), u'Jersy': (u'Jersy', u'JY', datetime.datetime(2014, 8, 13, 0, 0), 7), u'Alameda': (u'Alameda', u'CA', datetime.datetime(2014, 8, 13, 0, 0), 3)}