how to get last records of unique usernames from an array in java script

Question

I have an Array of Objects Like:

[ 
 { id: 8, username: \'peter\' ,weight:80,date:\'2019-10-14\'},
 { id: 1, username: \'harry\' ,weight:80,date:\'2019-01-01\'},         


        

Answer 1

Check the array from end for current object username and previous object username. If they are same break the loop, else push in the array.

const input =  [ 
      { id: 1, username: 'harry' ,weight:80,date:'2019-01-01'},
      { id: 2, username: 'harry' ,weight:84,date:'2019-02-21'},
      { id: 3, username: 'john' ,weight:80,date:'2019-03-11'},
      { id: 4, username: 'peter' ,weight:80,date:'2019-08-06'},
      { id: 5, username: 'peter' ,weight:80,date:'2019-06-11'},
      { id: 6, username: 'harry' ,weight:90,date:'2019-04-03'},
      { id: 7, username: 'john' ,weight:80,date:'2019-05-25'},
      { id: 8, username: 'peter' ,weight:80,date:'2019-10-14'},
];

const output = [];

for(let i = input.length-1; i > 0; i--) {
      if(input[i].username === input[i-1].username) {
          break;
      }
      output.push(input[i]);
}

console.log(output.sort((a, b) => a.date.localeCompare(b.date.localeCompare)));