This is code
for i = 1 : 5
b = i;
a=cumsum(b);
end
fprintf(\'%f \\n\', a);
I expected 1 + 2 + 3 + 4 + 5 = 15 so I would print 15 at t
cumsum
performs something like integration, where each element of the output is the sum of all elements up to that position (including) of the input vector.
Your code doesn't work because you pass a single value into cumsum
and there is no mechanism by which the previous result is saved, so you end up having only a single value, which is the last one - 5
.
You don't need a loop for this, nor even cumsum
- just write sum(1:5)
to get the desired result.