How to get the count of Custom tuples against two lists

Question

Please help me to get the counter for the list SS2 in list SS1 in PYTHON using from collections import Counter or any other fastest way

SS1 = [(1, 2, 3, 4, 5), (         


        

Answer 1

credit to @Chiheb Nexus

SS1=[(1, 2, 3, 4, 5), (1, 2, 3, 4, 6), (1, 2, 3, 5, 6), (1, 2, 4, 5, 6), (1, 3, 4, 5, 6), (2, 3, 4, 5, 6)]

from collections import Counter

def get_new_list(a, pos):
    # Check if any element in pos is > than the length of the tuples
    if any(k >= len(min(SS1, key=lambda x: len(x))) for k in pos):
        return

    for k in a:
        yield tuple(k[j] for j in pos)

def elm_counter(elm):
    if not len(elm):
        return 

    c = Counter(elm)
    for k, v in c.items():
        if v > 0:
            print(k, v)
elm = list(get_new_list(SS1, (2,)))
elm_counter(elm)
print('---')    
elm = list(get_new_list(SS1, (0, 2, 3)))
elm_counter(elm)
print('---')
elm = list(get_new_list(SS1, (1, 3, 4)))
elm_counter(elm)