bash Calculate age of person and read to csv file? [closed]

Answer 1

I think the core part of this problem is not adding the new age field to the end. but the age calculation.

try this:

awk -F'/|,' '{b=mktime($5" "$4" "$3" 00 00 00 00");a=(systime()-b)/(365*24*60*60);a=a==int(a)?a:int(a)+1;print $0","a}' file

well maybe I should not put them into one line:

awk -F'/|,' '{b=mktime($5" "$4" "$3" 00 00 00 00");
              a=(systime()-b)/(365*24*60*60);
              a=a==int(a)?a:int(a)+1;print $0","a}' file

test with your example data:

kent$  echo "Dave,ws245f,09/12/2000"|awk -F'/|,' '{b=mktime($5" "$4" "$3" 00 00 00 00");a=(systime()-b)/(365*24*60*60);a=a==int(a)?a:int(a)+1;print $0","a}' 
Dave,ws245f,09/12/2000,13

as you can see, I didn't check the title line, a NR>1 check could easily skip the title. You could DIY.

hope it helps