Remove character from array where spaces and punctuation marks are found [duplicate]

Answer 1

As I don't like the accepted answer, here's mine:

#include 
#include 
#include 

int main() {
    char str[100] = "str,, ing";
    int bad = 0;
    int cur = 0;
    while (str[cur] != '\0') {
        if (bad < cur && !ispunct(str[cur]) && !isspace(str[cur])) {
                str[bad] = str[cur];
        }
        if (ispunct(str[cur]) || isspace(str[cur])) {
            cur++;
        }
        else {
            cur++;
            bad++;
        }
    }
    str[bad] = '\0';
    fprintf(stdout, "cur = %d; bad = %d; str = %s\n", cur, bad, str);
    return 0;
}

Which outputs cur = 18; bad = 14; str = string

This has the advantage of being more efficient and more readable, hm, well, in a style I happen to like better (see comments for a lengthy debate / explanation).