Delete some informations in a json variable with php

Question

My problem is that i am parsing an XML file and this file contain some information that i don\'t want to exporting as JSON data. In my case i want a function that return the jso

Answer 1

Remove every attribute you don't want just before encoding json:

public function ParseXML ($url) {
    $fileContents= file_get_contents($url);
    // Remove tabs, newline, whitespaces in the content array
    $fileContents = str_replace(array("\n", "\r", "\t"), '', $fileContents);
    $fileContents = trim(str_replace('"', "'", $fileContents));
    $myXml = simplexml_load_string($fileContents);
    //--------------
    unset($myXml['@attributes']);
    unset($myXml['channel']);
    unset($myXml['image']);
    //--------------
    $json = json_encode($myXml);
    return $json;
}

or if you only need the item:

public function ParseXML ($url) {
    $fileContents= file_get_contents($url);
    // Remove tabs, newline, whitespaces in the content array
    $fileContents = str_replace(array("\n", "\r", "\t"), '', $fileContents);
    $fileContents = trim(str_replace('"', "'", $fileContents));
    $myXml = simplexml_load_string($fileContents);
    //--------------
    $json = json_encode($myXml['item']);
    return $json;
}