Thanks for looking.
Count how many numbers are less than 4 in an ordered array of numbers.
How do I increase the algorithm performance for longer array
You should use Array.BinarySearch
static int CountNumbers(int[] sortedArray, int lessThan)
{
if (sortedArray[0] >= lessThan) return 0;
int lengthOfArray = sortedArray.Length;
if (lengthOfArray == 0) return 0;
if (sortedArray[lengthOfArray - 1] < lessThan) return lengthOfArray;
int index = Array.BinarySearch(sortedArray, lessThan);
if (index < 0)
return ~index;
// Find first occurrence in case of duplicate
for (; index > 0 && sortedArray[index - 1] == lessThan; index--) ;
return index;
}