Implementing fuction that takes in array and multiplies each element by given int [duplicate]

Answer 1

When return i happens for the first time in your function, the function stops and returns the current i.

def multAll(A, k):
    return_value = []
    for i in A:
        i = i*k
        return_value.append(i)
    return return_value

Like this, a complete list return_value is created, and that list is returned.