Regex for parsing version number

Question

How can I write a regex for parsing version numbers. I want to match numbers like: 1.000, 1.0.00, 1.0.0.000 but not integers 1

Answer 1

I think you want something like this,

(?:(\d+\.[.\d]*\d+))

OR

(?:(\d+\.(?:\d+\.)*\d+))

DEMO

>>> import re
>>> str = 'foobar 1.000, 1.0.00, 1.0.0.000 10 100 foo bar foobar'
>>> m = re.findall(r'(?:(\d+\.(?:\d+\.)*\d+))', str)
>>> m
['1.000', '1.0.00', '1.0.0.000']