Write a Regex to extract number before '/'

Question

I don\'t want to use string split because I have numbers 1-99, and a column of string that contain \'#/#\' somewhere in the text.

How can I write a regex to extract the

Answer 1

import re
myString = "He got 10/19 questions right."
oldnumber = re.findall('[0-9]+/', myString)  #find one or more digits followed by a slash.
newNumber = oldnumber[0].replace("/","")  #get rid of the slash.

print(newNumber)
>>>10