Write a Regex to extract number before '/'

Question

I don\'t want to use string split because I have numbers 1-99, and a column of string that contain \'#/#\' somewhere in the text.

How can I write a regex to extract the

Answer 1

res = re.search('(\d+)/\d+', r'He got 10/19 questions right.')
res.groups()
('10',)