What is the point of adding and removing the element from Priority Queue in the given dijkstra code?

前端 未结 2 1991
再見小時候
再見小時候 2021-01-29 03:30

I was studying Dijkstra algorithm code given at this link -> https://java2blog.com/dijkstra-java/

Can someone explain the following 2 parts of the code?

1) Why a

2条回答
  •  醉梦人生
    2021-01-29 04:02

    To begin with, this code is bad, since priorityQueue.remove(v) requires O(n) time, which defeats the whole purpose of using PriorityQueue https://docs.oracle.com/en/java/javase/11/docs/api/java.base/java/util/PriorityQueue.html:

    ... linear time for the remove(Object) ...

    2) Dijkstra's algorithm in one phrase: select a non-visited vertex with a smallest distance. To extract the vertex with a smallest distance, you maintain a priority queue, where you compare vertices by distance (this is what your compareTo does). So the vertex which is extracted will be the vertex with the smallest distance.

    1) Data structures have some assumptions. If these assumptions are violated, data structures may work incorrectly. In case of PriorityQueue the assumption is "for any elements in the queue the result of comparison doesn't change". And, since you compare using distance, if you change the distance, then the result of comparison may also change, leaving your PriorityQueue in potentially invalid state. Therefore, you first remove the element, and only after that change the distance.

提交回复
热议问题