A function with a console log output inside console.log prints undefined

Question

function haha(){
  console.log(\'haha\');
}

console.log(haha());

Prints:

haha
undefined

Is it because if you don\'t

Answer 1

Is it because if you don't specify return in a function it will return undefined and this is what the second console.log is outputting?

Yes, console.log() prints the arguments passed to it. Arguments passed to it in the second time is the returned value of haha() which is undefined

First console log is the due to the console.log inside haha.