String has contents even though there is no input from user

Question

I am trying to \"trap\" keyboard inputs from user, meaning the code will prevent them from entering certain characters, which in this case prevents the input of numbers and spec

Answer 1

Reading uninitialised variables like done to buffe here:

if (c1=='\r' && strlen(buffe)==0)

provokes undefined behaviour, anything could happen afterwards. Do not do this.

Always initialise variable before reading them.

In this case you might like to simply do:

char buffe[32] = "";

or (as already proposed by others) the more generic way:

char buffer[32] = {0};

More complicated but also valid would be to do:

char buffer[32];
strcpy(buffe, "");

or

char buffer[32];
memset(buffe, 0, sizeof(buffe));