Assign address of one array to another in Perl possible?

Question

In the following C# code:

int[] X = new int[2];
X[0] = 1;
X[1] = 2;
int[] Y = X;
X[1] = 3;

After this executes, Y[1] will also be 3 since the o

Answer 1

In Perl an array is not a pointer.

You can get the reference of an array with the \ operator:

my @array = ( 1, 2 );
my $array_ref = \@array;

$array_ref will then point to the original array (as in C)

${$array_ref}[0] = 3

will change the first cell of the original array (i.e., $array[0] will be 3)