Shell command to get directory with least access date/time

Question

Is there any sort option available in find command to get directory with least access date/time

Answer 1

A simple shell script will also do:

unset -v oldest
for i in "$dir"/*; do
    [ "$i" -ot "$oldest" -o "$oldest" = "" ] && oldest="$i"
done

note: to find the oldest directory use "$dir"/*/ above (thanks Cyrus) and -type d below with the find command.

In bash if you need a recursive solution, then you can rewrite it as a while loop with process substitution using find

unset -v oldest
while IFS= read -r i; do
    [ "$i" -ot "$oldest" -o "$oldest" = "" ] && oldest="$i"
done < <(find "$dir" -type f)