java.lang.IllegalArgumentException: Failed to register servlet with name 'dispatcher'.Check if there is another servlet registered under the same name

Question

My initializer class

public class HomeServlet extends 
AbstractAnnotationConfigDispatcherServletInitializer{

@Override
protected Class         


        

Answer 1

1. use the configuration class as follows:

   @ComponentScan(basePackages={"spittr.controllers"})
   @Configuration
   @EnableWebMvc
   public class SpringContextConfig1 extends WebMvcConfigurerAdapter{
   
       @Override            
       public void configureViewResolvers(ViewResolverRegistry registry) {
           InternalResourceViewResolver ivr=new InternalResourceViewResolver();
           ivr.setPrefix("/WEB-INF/jsp/");
           ivr.setSuffix(".jsp");
           ivr.setExposeContextBeansAsAttributes(true);
           registry.viewResolver(ivr);
       }
   }
   

   Basically you're extending WebMvcConfigurerAdapter without inheriting any of its methods (in my 4.3.3 Spring version al least).

2. since you have a single DispatcherServlet here, you can add the SpringContextConfig1 class to the root context and leave the servlet context empty: switch the body of the method getServletConfigClasses() under the getRootConfigClasses() and vice versa - see A Bit on ApplicationContext Hierarchies.

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Moreover, the DispatcherServlet mapping is more likely / instead of /home:

protected String[] getServletMappings() {
    return new String[] {"/"};
}