output : prime numbers 2 3 () 5 () 7 () ()
i want as 2 3 5 7
def primeNumber(range: Int): Unit ={
val primeNumbers: immutable.IndexedSeq[AnyVal] =
The reason is if else returning two types of value one is prime value and another is empty. You could return 0 in else case and filter it before printing it.
scala> def primeNumber(range: Int): Unit ={
|
| val primeNumbers: IndexedSeq[Int] =
|
| for (number :Int <- 2 to range) yield{
|
| var isPrime = true
|
| for(checker : Int <- 2 to Math.sqrt(number).toInt if number%checker==0 if isPrime) isPrime = false
|
| if(isPrime) number
| else
| 0
| }
|
| println("prime numbers" + primeNumbers)
| for(prime <- primeNumbers.filter(_ > 0))
| println(prime)
| }
primeNumber: (range: Int)Unit
scala> primeNumber(10)
prime numbersVector(2, 3, 0, 5, 0, 7, 0, 0, 0)
2
3
5
7
But we should not write the code the way you have written it. You are using mutable variables. Try to write code in an immutable way. For example
scala> def isPrime(number: Int) =
| number > 1 && !(2 to number - 1).exists(e => e % number == 0)
isPrime: (number: Int)Boolean
scala> def generatePrimes(starting: Int): Stream[Int] = {
| if(isPrime(starting))
| starting #:: generatePrimes(starting + 1)
| else
| generatePrimes(starting + 1)
| }
generatePrimes: (starting: Int)Stream[Int]
scala> generatePrimes(2).take(100).toList
res12: List[Int] = List(2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100, 101)