Haskell check if chess board diagonal movement is True or False [closed]

Answer 1

If you want to check if a point (x,y) is on the same diagonal as a point (x',y') in Haskell, a good place to start is with a type.

isDiagonal :: (Int, Int) -> (Int, Int) -> Bool

Whilst technically optional, it's good practice to give every top level function an explicit type.

Now, we need a body for this function.

isDiagonal (x, y) (x', y') = ...

If they're on the same diagonal, then x and x' must be as far apart from each other as y and y' are. So we can just check if the differences are equal. i.e

abs (x - x') == abs (y - y')

Putting it all together, we (hopefully) arrive at the desired function

isDiagonal :: (Int, Int) -> (Int, Int) -> Bool
isDiagonal (x, y) (x', y') = abs (x - x') == abs (y - y')

There's no need for && here, at all. But we could use it, if for example we wanted to impose an extra condition, like the new points must be on the 4x5 board (assuming 1-indexing)

isDiagonal :: (Int, Int) -> (Int, Int) -> Bool
isDiagonal (x, y) (x', y') = x' >= 1 && x' <= 4 && 
                             y' >= 1 && y' <= 5 &&
                             abs (x - x') == abs (y - y')