C - Dereferencing void pointer

Question

I\'m trying to create my own swap function but I have troubles.
Why I\'m getting \" dereferencing void pointer \" ?

void    ft_swap(void *a, void *b, size         


        

Answer 1

Because you are dereferencing void pointers:

void    ft_swap(void *a, void *b, size_t nbytes)
{
 ...
        cur_a = (unsigned char *)*a + i; // here
        cur_b = (unsigned char *)*b + i; // here

Doing *a means you first dereference a, and then you cast the result (whatever that is, dereferencing void* doesn't make much sense) to a pointer to unsigned char. Doing

cur_a = *((unsigned char *)a) + i;

makes more sense.