Find the durations and their maximum between the dataset in an interval in shell script

Question

This is related to my older question Find the durations and their maximum between the dataset in shell script

I have a dataset as:

ifile.txt
2
3
2
3
2
20         


        

Answer 1

A format command added to the EDIT2 solution given by RavinderSingh13 which will print exact desire output:

awk '
$0!=0{
  count++
  max=max>$0?max:$0
  found=""
}
$0==0{
  print count,max
  count=max=0
  next
}
FNR%6==0{
  print count,max
  count=max=0
  found=1
}
END{
  if(!found){
      print count,max
  }
}
'  Input_file | awk '!/^ /' | awk '$1 != 0'

Output will be as follows.

6 20
1 2
1 2
1 2
5 7
1 3
3 5

---

---

EDIT2: Adding another solution which will print values in every 6 elements along with zeros coming in between.

awk '
$0!=0{
  count++
  max=max>$0?max:$0
  found=""
}
$0==0{
  print count,max
  count=max=0
  next
}
FNR%6==0{
  print count,max
  count=max=0
  found=1
}
END{
  if(!found){
      print count,max
  }
}
'  Input_file

Output will be as follows.

6 20
1 2
1 2
0 0
1 2
5 7
1 3
3 5

---

---

EDIT: As per OP's comment OP doesn't want to reset of count of non-zeros when a zero value comes in that case try following.

awk '
$0!=0{
  count++
  max=max>$0?max:$0
  found=""
}
FNR%6==0{
  print count,max
  count=max=0
  found=1
}
END{
  if(!found){
      print count,max
  }
}
'  Input_file

Output will be as follows.

6 20
3 2
5 7
.......

---

---

Could you please try following(written and tested with posted samples only).

awk '
$0!=0{
  count++
  max=max>$0?max:$0
  found=""
}
$0==0{
  count=FNR%6==0?count:0
  found=""
}
FNR%6==0{
  print count,max
  count=max=0
  found=1
}
END{
  if(!found){
      print count,max
  }
}
'  Input_file