ASP.NET MVC, Bootstrap Tables, get values for each column

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说谎
说谎 2021-01-28 13:33

In ASP.NET MVC, I\'ve an action which takes user input about rows and columns and then it navigates to the action which generates required number of rows and columns based on th

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  •  醉梦人生
    2021-01-28 14:09

    Create view models that represent what you want to display/edit

    public class TableVM
    {
      public TableVM()
      {
        Rows = new List();
      }
      public TableVM(int rows, int columns) : this()
      {
        for(int i = 0; i < rows; i++)
        {
          Rows.Add(new RowVM(columns));
        }
      }
      public List Headers { get; set; } // for columns headers
      public List Rows { get; set; }
    }
    public class RowVM
    {
      public RowVM()
      {
        Cells = new List();
      }
      public RowVM(int columns) : this()
      {
        for(int i = 0; i < columns; i++)
        {
          Cells.Add(new CellVM());
        }
      }
      public List Cells { get; set; }
    }
    public class CellVM
    {
      public string Value { get; set; }
    }
    

    and in the GET method, initialize a new TableVM and return it to the view

    TableVM model = new TableVM(5, 5); // 5 x 5 grid
    model.Headers = new List{ "col 1", "col 2", "col 3", col 4", "col 5" };
    return View(model);
    

    View

    @model TableVM
    ....
    
          @foreach(string header in Model.Headers)
          {
            
          }
        
        @for(int r = 0; r < Model.Rows.Count; r++)
        {
          
            for (int c = 0; c < Model.Rows[r].Cells.Count; c++)
            {
              
            }
          
        }
      
    @header
    @Html.TextBoxFor(m => m.Rows[r].Cells[c].Value

    Then change you POST method to accept the model

    [HttpPost]
    public ActionResult Enter(TableVM model)
    

    You can now access each row/column using indexers, for example model.Rows[1].Cells[2].Value will return the value of the 3rd column in the second row

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