Eq => function in Haskell

Question

I am trying to figure out how to write this function with the Eq function in Haskell.

An easy function that I am trying to implement is:

f :: Eq a =>          


        

Answer 1

You can also use span and a recursive call to make it work:

f :: Eq a => [a] -> [[a]]
f [] = []
f l@(x:xs) = grouped : f remainder
    where
        (grouped, remainder) = span (== x) l

Here you have the live example