The issue with 8.3 is.....rank is introduced in 8.4.
consider the numbers [10,6,6,2]
I wish to achieve a rank of those numbers where the rank is equal to the th
Do you have a PK for this table?
Just self join and count items with: a higher or equal score and higher PK.
PK comparison will break ties and give you desired result.
And after you upgrade to 9.1 - use row_number().
row_number()