Bob Counter in Python

Question

Using Python 2.7, I was attempting to count the number of occurances of \'bob\' in the phrase \'bobbbobobboobobookobobbobbboj.\' To do this, I wrote the code below:

Answer 1

s = ('bobobobobobob')
count = 0

for i in range(len(s)):
    if s[i:i+3] == "bob":
        count += 1

print ('Number of times bob occurs is: ' + str(count))