mySQL query multiple - returns error mysql_fetch_array

Question

I have 2 database tables (for a booking system) with the following structures:

quartos:

• id_quarto.
• tipo_quarto

Answer 1

You forget about mysql_query, change:

// Select database
mysql_select_db("teste") or die(mysql_error());

// Get data from the database

$strSQL = "SELECT id_quarto,tipo_quarto,vista_quarto FROM quartos,reservas WHERE quartos.id_quarto!=reservas.id_quarto AND quartos.tipo_quarto='". $_POST['tipo_quarto'] ."' AND quartos.vista_quarto='". $_POST['vista_quarto'] ."'";

// Loop the recordset $rs
// Each row will be made into an array ($row) using mysql_fetch_array
while($row = mysql_fetch_array($rs)) {

to:

// Select database
mysql_select_db("teste") or die(mysql_error());

// Get data from the database

$strSQL = "SELECT q.id_quarto, q.tipo_quarto, q.vista_quarto ".
          " FROM quartos q, reservas r".
          " WHERE q.id_quarto != r.id_quarto ".
          " AND q.tipo_quarto = '". mysql_real_escape_string($_POST['tipo_quarto']) ."' ".
          " AND q.vista_quarto = '". mysql_real_escape_string($_POST['vista_quarto']) ."'";

$rs = mysql_query($strSQL);

// Loop the recordset $rs
// Each row will be made into an array ($row) using mysql_fetch_array
while($row = mysql_fetch_array($rs)) {

Added: Prevent SQL injection using mysql_real_escape_string on each parameter from user.