How to tell a RegEx to be greedy on an 'Or' Expression

Question

Text:

[A]I\'m an example text [] But I want to be included [[]]
[A]I\'m another text without a second part []

Regex:

\\[A\\][\\         


        

Answer 1

I have changed your regex (actually simpler) to do what you want:

\[A\].*\[?\[\]\]?

It starts by matching the '[A]', then matches any number of any characters (greedy) and finally one or two '[]'.

Edit:

This will prefer double Square brackets:

\[A\].*(?:\[\[\]\]|\[\])