I need help coming up with a function in python that can take 3 arguements as lists and give me all combinations of there elements [duplicate]

Answer 1

Use itertools.product:

def dress_me(shirt, tie, suit):
    if type(shirt) != list or type(tie) != list or type(suit) != list:
        return None
    return list(itertools.product(shirt, tie, suit))

Demo:

>>> dress_me([1,2,3],[4,5,6],[7,8,9])
[(1, 4, 7), (1, 4, 8), (1, 4, 9), (1, 5, 7), (1, 5, 8), (1, 5, 9), (1, 6, 7), (1, 6, 8), (1, 6, 9), (2, 4, 7), (2, 4, 8), (2, 4, 9), (2, 5, 7), (2, 5, 8), (2, 5, 9), (2, 6, 7), (2, 6, 8), (2, 6, 9), (3, 4, 7), (3, 4, 8), (3, 4, 9), (3, 5, 7), (3, 5, 8), (3, 5, 9), (3, 6, 7), (3, 6, 8), (3, 6, 9)]