Converting a list of ints, tuples into an numpy array

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太阳男子
太阳男子 2021-01-28 09:17

I have a list of [float, (float,float,float..) ] ... Which is basically an n-dimensional point along with a fitness value for each point. For eg.

4.3, (2,3,4)
         


        
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  •  广开言路
    2021-01-28 09:49

    The following should work:

    A = np.array([tuple(i) for i in initial_list],dtype=[('fitness',float),('point',(float,3))])
    

    with initial_list = [[4.3, (2, 3, 4)], [3.2, (1, 3, 5)], ...]. Note that we need to transform each item of initial_list into a tuple for that trick to work, else NumPy cannot recognize the structure.

    Your fitness entries are now accessible as A['fitness'], with the corresponding points as A['point']. If you select a list of actual fitness entries, indices, the corresponding points are given by A['point'][indices], which is a simple (n,3) array.

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