I have a list of [float, (float,float,float..) ] ... Which is basically an n-dimensional point along with a fitness value for each point. For eg.
4.3, (2,3,4)
The following should work:
A = np.array([tuple(i) for i in initial_list],dtype=[('fitness',float),('point',(float,3))])
with initial_list = [[4.3, (2, 3, 4)], [3.2, (1, 3, 5)], ...]
. Note that we need to transform each item of initial_list
into a tuple for that trick to work, else NumPy cannot recognize the structure.
Your fitness entries are now accessible as A['fitness']
, with the corresponding points as A['point']
. If you select a list of actual fitness entries, indices
, the corresponding points are given by A['point'][indices]
, which is a simple (n,3)
array.