char [length] initialization and dealing with it

Question

I have defined a char array:

char d[6];

Correct me if I\'m wrong regarding following:

At this moment no memory is allocated for variabl

Answer 1

Your code will not compile (gcc 4.6.3) if you do

 char d[6];
 d = "aaaaa";

you will need to do

 char d[6] = "aaaaa" 

to initialise it this way. This is a local variable created on the stack and so in terms of memory issues all you need worry about is not writing/reading beyond the array bounds.