How to make the argument to filter() a variable?

Question

I have this model

class Item(db.Model):
    ...   
    glam = db.StringProperty()
    casual = db.StringProperty()
    speaking = db.StringProperty()
         


        

Answer 1

Would that do what you're looking for:

choice = self.request.get("tag")
query.filter(choice, choice)

However, I agree with Wooble below. The way you have designed it, you dont' really use glam, casual, speaking as StringProperty, since they are either empty or have a specific value.

What you probably want to do is have a tag property that can take different values from glam, formal, speaking, ...

class Item(db.Model):
    ...   
    tag = db.StringProperty()

And then you would query your db like so:

query.filter("tag", self.request.get("tag"))