MySpecialView
is a complex image control, I would like to reuse it from different views and pass its ViewModel
as in this example.
MainWindow.x
Do not specify viewmodel property in you view, use DataContext. See the following code.
public partial class MySpecialView : UserControl
{
public MySpecialView()
{
InitializeComponent();
}
}
ViewModel for special:
public class MySpecialViewModel : ViewModelBase
{
public BitmapSource imageSource { get; set; }
public BitmapSource ImageSource { get { return imageSource; }
set { if (value != imageSource)
{
imageSource = value;
RaisePropertyChanged("ImageSource");
}
} }
public MySpecialViewModel()
{
//gets displayed
ImageSource = new BitmapImage(new Uri("C:\\Users\\user\\Pictures\\test.jpg"));
//gets displayed aswell
Task.Run(() => changeImage(10000, "C:\\Users\\user\\Pictures\\clickMe.png"));
}
public async void changeImage(int sleep, string uri)
{
await Task.Delay(sleep);
BitmapSource source = new BitmapImage(new Uri(uri));
source.Freeze();
ImageSource = source;
}
}
In XAML special:
For main:
public class MainViewModel : ViewModelBase
{
public MySpecialViewModel SpecialViewModel
{
get { return _specialViewModel; }
set
{
if (value != _specialViewModel)
{
_specialViewModel= value;
RaisePropertyChanged("SpecialViewModel");
}
}
}
private MySpecialViewModel _specialViewModel;
public MainViewModel()
{
MySpecialViewModel = new MySpecialViewModel();
//gets not displayed!
Task.Run(() => MySpecialViewModel.changeImage(5000, "C:\\Users\\user\\Pictures\\Capture.PNG"));
}
}
And in XAML: