Get content of webservice

Question

I\'ve got an URL like here. When I type that into Safari\'s address bar I see an result like \"Error\" or \"OK\".

So, how do I properly call that URL from within my code

Answer 1

The "response" in those classes refers to the protocol response (HTTP headers, etc.), not the content.

To get the content, you have a few options:

1. Use NSURLConnection in asynchronous mode: Using NSURLConnection

2. Use NSURLConnection in synchronous mode:

   // Error checks omitted
   NSURL *URL = [NSURL URLwithString:@"http://www.myserver.com/myservice.php?param=foobar"];
   NSURLRequest *request = [NSURLRequest requestWithURL:URL];
   NSData *data = [NSURLConnection sendSynchronousRequest:request
                                        returningResponse:nil
                                                    error:nil];
   

3. Use [NSString stringWithContentsOfURL:]

   NSURL *URL = [NSURL URLwithString:@"http://www.myserver.com/myservice.php?param=foobar"];
   NSString *content = [NSString stringWithContentsOfURL:URL];
   

Of course, you should use options 2 and 3 only if your content will be really small in size, to maintain responsiveness.