Return from a method in which forEach() array method was called. JavaScript

Question

I am using forEach() method called from an array in JavaScript. When I write return; somewhere inside the method which is called for every element in array I return

Answer 1

You could do the following, with Array#find:

function addToCart(pizza, size)
{
    // find the first item where the condition is true, 
    // or undefined if there is none
    var sameSizeItem = Cart.find(function (item) {
        return pizzaAndSizeAreTheSame(item, pizza, size);
    });

    if (sameSizeItem) {
        sameSizeItem.quantity++;
        updateCart();
        return;
    }

    Cart.push({
        pizza: pizza,
        size: size,
        quantity: 1
    });

    updateCart();
}

A little more adjustment and you can avoid having updateCart() in two different places:

function addToCart(pizza, size)
{
    // find the first item where the condition is true, 
    // or undefined if there is none
    var sameSizeItem = Cart.find(function (item) {
        return pizzaAndSizeAreTheSame(item, pizza, size);
    });

    if (sameSizeItem) {
        sameSizeItem.quantity++;
    } else {
        Cart.push({
            pizza: pizza,
            size: size,
            quantity: 1
        });
    }

    updateCart();
}

If the environment(s) you're targeting do not all support Array#find, you can get a polyfill from MDN.