a = {0: \'PtpMotion\', 1: \'PtpMotion\', 2: \'LinMotion\', 3: \'LinMotion\', 4: \'LinMotion\', 5: \'LinMotion\', 6: \'LinMotion\', 7: \'LinMotion\', 8: \'LinMotion\', 9:
Each key can only occur once in a dictionary. You could store a list of indices for each key:
import collections
b = collections.defaultdict(list)
for key, val in a.iteritems():
b[val].append(key)
print b
# {'LinMotion': [2, 3, 4, 5, 6, 7, 8, 10], 'PtpMotion': [0, 1, 9], 'Wait': [11]}
Edit: As pointed out by ecik in the comments, you could also use a defaultdict(set)
(and use .add()
instead of .append()
in the loop).