What does it mean by java.lang.ArrayIndexOutOfBoundsException : 0

Question

my compiler keep pointing at this line:

arr[i] = new specialDelivery(name,name2,weight,special);

and this :

arr[i] = new specia         


        

Answer 1

From your code:

int size = 0;
...
Parcel arr[] = new Parcel[size];

Therefore, you've created an array with length 0. Since arr[0] attempts to access the first element, but a zero-length array has zero elements, you get that exception. You will have to either allocate the array with an appropriate non-zero size, or use a dynamic container such as an ArrayList.