Summarize a list of dictionaries based on common key values

Question

I have a list of dictionaries like so:

dictlist = [{\'day\': 0, \'start\': \'8:00am\', \'end\': \'5:00pm\'},
            {\'day\': 1, \'start\': \'10:00am\', \'e         


        

Answer 1

You can use itertools.groupby like this.

source code:

from itertools import groupby
for k, grp in groupby(sorted(dictlist, key=lambda x:(x['end'], x['start'])), key=lambda x:(x['start'], x['end'])):
    print [i['day'] for i in grp], k

output:

[5] ('11:00am', '1:00pm')
[0, 2, 4] ('8:00am', '5:00pm')
[1, 3] ('10:00am', '7:00pm')

But I think using defaultdict(@Akavall answer) is the right way in this particular case.