Grouping Nodes by hardcoding node values in XSLT

Question

   
      1
      

         A1
         1000
      <         


        

Answer 1

If you have the option of using for-each-group, I'd definitely use that over Muenchian grouping...

Fiddle: http://xsltfiddle.liberty-development.net/jxNakzX

If you truly want to hard code the "A" -> A1, A2 and "B" -> B1, B2 mapping, you could use xsl:key and not group at all...

Fiddle: http://xsltfiddle.liberty-development.net/jxNakzX/1