PHP Function Argument to an array

Question

Can you do something crazy like this

function cool_function($pizza, $ice_cream) { 

   make the arguments in the array into an array 
   return $array_of_parama         


        

Answer 1

I'm not sure if you're looking for func_get_args which return all arguments passed to a function, or the ReflectionFunction class.

A basic example of func_get_args:

function cool_function($pizza, $ice_cream) { 
   return func_get_args();
}

But you don't need the arguments to make this work:

function cool_function() { 
   return func_get_args();
}
// cool_function(1,2,3) will return array(1,2,3)

The reflection option:

/**
 * Returns an array of the names of this function
 */
function getMyArgNames($a,$b,$c)
{
    $args = array();
    $refFunc = new ReflectionFunction(__FUNCTION__);
    foreach( $refFunc->getParameters() as $param ){
         $args[] = $param->name;
    }
    return $args;
}

Or, for the really crazy:

/**
 * Returns an associative array of the names of this function mapped 
 * to their values
 */
function getMyArgNames($a,$b,$c)
{
    $received = func_get_args();
    $i = 0;
    $args = array();
    $refFunc = new ReflectionFunction(__FUNCTION__);
    foreach( $refFunc->getParameters() as $param ){
         $args[$param->name] = $received[$i++];
    }
    // include all of those random, optional arguments.
    while($i < count($received)) $args[] = $received[$i++];
    return $args;
}