I have one dictionary that contains an Array of Dictionaries.
\"other\":(
{
\"grocery_section\" = other,
name = test
},
{
You can make use of flatMap
and compactMap
:
let matches = list.flatMap { key, value in
// go through all elements in the array and convert the matching dictionaries in (key, index) pairs
value.enumerated().compactMap { index, dict in
dict["name"] == "test" ? (key, index) : nil
}
}
print(matches)
Sample output:
[("other", 0), ("c0f5d6c5-4366-d310c0c9942c", 1)]
If you want to avoid repeated pairs for the same key, you can use map
instead of compactMap
:
let matches = list.map { key, value in
(key, value.enumerated().compactMap { index, dict in
dict["name"] == "test" ? index : nil
})
}
Sample output:
[("other", [0]), ("c0f5d6c5-4366-d310c0c9942c", [1])]
The inner compactMap
will build an array made of on only the items that have the name matching, while the outer flatMap
will flatten an otherwise bi-dimensional array.