Replacing last characters after last comma with a string

Question

I have a huge text file which look like this:

36,53,90478,0.58699759849,0.33616,4.83449759849,0.0695335954050315,3
36,53,90478,0.58699759849,0.33616,4.8344975984         


        

Answer 1

This is the answer that @RomanPerekhrest provided at my cross-question (I was also seeking unix/perl solutions) here:

awk approach with sprintf function(to add leading zeros):

 awk -F, -v OFS=',' '$8="MI-"sprintf("%02d",$8);' file

The output:

36,53,90478,0.58699759849,0.33616,4.83449759849,0.0695335954050315,MI-03
36,53,90478,0.58699759849,0.33616,4.83449759849,0.0695335954050315,MI-08
36,53,90478,0.58699759849,0.33616,4.83449759849,0.0695335954050315,MI-14
36,53,15596,0.58454577855,0.26119,2.24878677855,0.116147072052964,MI-12